2[m-(3m+19)+16]=2(m+3)

Solution for 2[m-(3m+19)+16]=2(m+3) equation:

Simplifying
2[m + -1(3m + 19) + 16] = 2(m + 3)

Reorder the terms:
2[m + -1(19 + 3m) + 16] = 2(m + 3)
2[m + (19 * -1 + 3m * -1) + 16] = 2(m + 3)
2[m + (-19 + -3m) + 16] = 2(m + 3)

Reorder the terms:
2[-19 + 16 + m + -3m] = 2(m + 3)

Combine like terms: -19 + 16 = -3
2[-3 + m + -3m] = 2(m + 3)

Combine like terms: m + -3m = -2m
2[-3 + -2m] = 2(m + 3)
[-3 * 2 + -2m * 2] = 2(m + 3)
[-6 + -4m] = 2(m + 3)

Reorder the terms:
-6 + -4m = 2(3 + m)
-6 + -4m = (3 * 2 + m * 2)
-6 + -4m = (6 + 2m)

Solving
-6 + -4m = 6 + 2m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2m' to each side of the equation.
-6 + -4m + -2m = 6 + 2m + -2m

Combine like terms: -4m + -2m = -6m
-6 + -6m = 6 + 2m + -2m

Combine like terms: 2m + -2m = 0
-6 + -6m = 6 + 0
-6 + -6m = 6

Add '6' to each side of the equation.
-6 + 6 + -6m = 6 + 6

Combine like terms: -6 + 6 = 0
0 + -6m = 6 + 6
-6m = 6 + 6

Combine like terms: 6 + 6 = 12
-6m = 12

Divide each side by '-6'.
m = -2

Simplifying
m = -2